Home
/
1. csc pi/6 - sec pi/3 2. cos pi/4 tan pi/6 + 2tan pi/3 How to solve both?
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Verified answer
1. csc pi/6 - sec pi/3 =
1/(sinπ/6) - 1/(cosπ/3) = 1/(1/2) - 1/(1/2) = 2 -2 = 0
2. cos pi/4 tan pi/6 + 2tan pi/3 =
1/√2 * sinπ/6/ (cosπ/6) + 2* sinpi/3/(cospi/3) =
= 1/√2 * 1/2/ (√3/2) + 2* √3/2/(1/2) =
= 1/√2*1/√3 + 2*√3 = √2*√3/6 + 2√3 = √3 (2 + √2/6)
csc(x) = 1/sin(x)
sec(x) = 1/cos(x)
tan(x) = sin(x)/cos(x)
These are all standard values, so you just write down the known values. For instance csc(pi/6) = 1/sin(pi/6) and you should know the sine of pi/6 is 0.5, so 1/0.5 = 2.
UNIT CIRCLE and DEFINITIONS OF TRIGONOMETRIC FUNCTIONS !!
csc Θ = 1 / sin Θ
sec Θ = 1 / cos Θ
csc (π/6) = 2 [1 / sin (π/6) = 1 / (1/2) = 2 ]
sec (π/3) = 2 [1 / cos (π/3) = 1 / (1/2) = 2 ]
You should go to your teacher for help...this is FUNDAMENTAL !!
one at a time