1. Find the equation of a line that passes through the points(8, 7) and (5, -10).
Home
/
1. Find the equation of a line that passes through the points(8, 7) and (5, -10).
1. Find the equation of a line that passes through the points(8, 7) and (5, -10).
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Verified answer
Answer:
Using m = y2 - y1 / x2 - x1, solve for the slope:
m = (-10 - 7) / (5 - 8)
Calculate the difference.
m = -17 / -3
Simplify the fraction.
m = 17/3
Using y = mx + b, substitute all given terms.
{-10 = 17/3(5) + b
{7 = 17/3(8) + b
Calculate the product.
{-10 = 85/3 + b
{7 = 136/3 + b
Move b to the left-hand side and change its sign.
{-10 - b = 85/3
{7 - b = 136/3
Move the constants to the right-hand side and change its sign.
{-b = 85/3 + 10
{-b = 136/3 - 7
Calculate the sum and difference.
{-b = 115/3
{-b = 115/3
When -b = 115/3 is already written, it does not have to be written again.
-b = 115/3
Divide both sides by -1.
b = -115/3
The equation of the line in slope-intercept form is y = 17/3x - 115/3