1. If pentagon has ratio of 3:2:3:2:5. What is the length of each sid3 if the perimeter is 30 m?
2. Four angles of a pentagon have the following measures : 72°,121°,108° and 124°.
What is the measure of the remaining angle?
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1. If pentagon has ratio of 3:2:3:2:5. What is the length of each sid3 if the perimeter is 30 m?
2. Four angles of a pentagon have the following measures : 72°,121°,108° and 124°.
What is the measure of the remaining angle?
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Answer:
1. 6 m
2.
Step-by-step explanation:
I dont know the area on number 2 so i can't help you
Answer:
#1.
Without memorizing any formula, Perimeter is simply all the sum of the sides enclosing a figure.
Since it's a pentagon, it will have 5 sides.
So
P = side1 + side2 + side3 + side4 + side5
given sides are in ratio:
side1 = 3x
side2 = 2x
side3 = 3x
side4 = 2x
side5 = 5x
So Permieter is simply sum of all 5 sides
30 = 3x + 2x + 3x + 2x + 5x
30 = 15x
x = 30/15
x = 2 m
so the sides are measured as follows:
side1 = 3x = 3(2) = 6m
side2 = 2x = 2(2) = 4m
side3 = 3x = 3(2) = 6m
side4 = 2x = 2(2) = 4m
side5 = 5x = 5(2) = 10m
#2.
The sum of the internal angles in a pentagon is 540°
so,
72 + 121 +108 + 124 + x = 540
where x is the 5th or remaining angle
425 + x = 540
x = 540 - 425
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