1. The batter hits the softball and it follows a path in which h is given by
h(t)
=-8t²+ 16+ + 5, where t is the time in seconds elapsed since the ball
was pitched. What is the maximum height reached by the softball?
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1. The batter hits the softball and it follows a path in which h is given by
h(t)
=-8t²+ 16+ + 5, where t is the time in seconds elapsed since the ball
was pitched. What is the maximum height reached by the softball?
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Answer:
t=-h- h raise to the second power +672
Step-by-step explanation: