1.) The graph of 2x - 8x + k = 0 crossed the x-axis twice. What is the value k?
2.) find the value of k in the equation 4x²-6x+4 (k-1) = 0 if its has only one solution.
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1.) The graph of 2x - 8x + k = 0 crossed the x-axis twice. What is the value k?
2.) find the value of k in the equation 4x²-6x+4 (k-1) = 0 if its has only one solution.
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Answer:
1. 12x
2. 13x
that's the answer
Step-by-step explanation:
2x-8x =6x
so the value of k is now 6x
and again plus it to the value of k
6x+6x=12x
2. 4x2-6x=10
10+4= 14x
the value of k is now 14x
now minus it 1
14-1=13x