1. There are 90 pupils in the library. The girls are 28 more than the boys. How
many girls are there?
Let x = the number of boys.
x + 28 = the number of girls
Solution:
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1. There are 90 pupils in the library. The girls are 28 more than the boys. How
many girls are there?
Let x = the number of boys.
x + 28 = the number of girls
Solution:
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[tex]\large \bold {QUESTION:}[/tex]
There are 90 pupils in the library. The girls are 28 more than the boys. How many girls are there?
[tex]\large \bold {GIVEN:}[/tex]
Let x = the number of boys.
x + 28 = the number of girls
[tex]\large \bold {SOLUTION:}[/tex]
First, we have to find x and we will do that by equating the expressions with 90 since there are 90 pupils in total. That is,
[tex] \large \tt x + (x + 28) = 90 \\ \\ \large \tt x + x + 28 = 90 \: \: \: \\ \\ \large \tt 2x + 2 8 = 90 \: \: \: \: \: \: \: \: \: \\ \\ \large \tt 2x = 90 - 28 \: \: \: \: \: \: \: \: \: \\ \\ \large \tt 2x = 62 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \large \tt \frac{2x}{2} = \frac{62}{2} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \large { \boxed{\tt x = 31}} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: [/tex]
Now that we have the value of x, we will substitute it to x+28
[tex] \large \tt number \: of \: girls = x + 28 \: \: \: \: \: \: \\ \\ \large \tt number \: of \: girls = (31) + 28 \\ \\ \large \red{ \boxed{ \tt number \: of \: girls = 59}} \: \: \: \: \: \: \: \: \: \: \: \: \: [/tex]
[tex]\large \bold {CONCLUSION:}[/tex]
∴ There are 59 girls in the library.
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