1.) V44 + 11
Solution:
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1.) V44 + 11Solution:
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Answer:
sana makatulong
Step-by-step explanation:
Changes made to your input should not affect the solution:
(1): "v1" was replaced by "v^1". 1 more similar replacement(s).
STEP
1
:
STEP
2
:
Pulling out like terms
2.1 Pull out like factors :
v44 - v11 = v11 • (v33 - 1)
Trying to factor as a Difference of Cubes:
2.2 Factoring: v33 - 1
Theory : A difference of two perfect cubes, a3 - b3 can be factored into
(a-b) • (a2 +ab +b2)
Proof : (a-b)•(a2+ab+b2) =
a3+a2b+ab2-ba2-b2a-b3 =
a3+(a2b-ba2)+(ab2-b2a)-b3 =
a3+0+0-b3 =
a3-b3
Check : 1 is the cube of 1
Check : v33 is the cube of v11
Factorization is :
(v11 - 1) • (v22 + v11 + 1)
Trying to factor by splitting the middle term
2.3 Factoring v22 + v11 + 1
The first term is, v22 its coefficient is 1 .
The middle term is, +v11 its coefficient is 1 .
The last term, "the constant", is +1
Step-1 : Multiply the coefficient of the first term by the constant 1 • 1 = 1
Step-2 : Find two factors of 1 whose sum equals the coefficient of the middle term, which is 1 .
-1 + -1 = -2
1 + 1 = 2
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
Final result :
v11 • (v11 - 1) • (v22 + v11 + 1)