12. Subtract the product of 8 and 6 from a number. Then divide the result by the difference of 46 and 37. Add 19 afterwards and the results is 23. What is the original number?
A.84
B.36
C.9
D. 4
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12. Subtract the product of 8 and 6 from a number. Then divide the result by the difference of 46 and 37. Add 19 afterwards and the results is 23. What is the original number?
A.84
B.36
C.9
D. 4
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Answer:
First Multiply 8 and 6
[tex]8 \times 6 = 48[/tex]
Then subtract the 48 in 8 and 6, but first lets subtract it to 8.
[tex]48 - 8 = 40[/tex]
[tex]48 - 6 = 42[/tex]
Then Divide it by subtracting another numbers 46 and 37.
[tex]46 - 37 = 9[/tex]
Divide 9 to result in the first subtracted numbers 40 and 42.
[tex]40 \div 9 = 4\pi4[/tex]
[tex]42 \div 9 = 4\pi6[/tex]
Next , add 19 in the results in division
[tex]4 + 19 = 23[/tex]
[tex]4 + 19 = 23[/tex]
And the original number is 4
So the answer is letter D.
Hope It Helps
Answer:
Hi po salamat po Wala Akong Sagot 0