15.5L of a gas is known to contain 0.965 mol. If the amount of gas is increased to 5.80 mol, what new volume will result (at an unchanged temperature and pressure)?
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15.5L of a gas is known to contain 0.965 mol. If the amount of gas is increased to 5.80 mol, what new volume will
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Answer:
The volume of a gas is directly proportional to the number of moles of the gas, at a constant temperature and pressure. This relationship is described by Avogadro's law, which states that equal volumes of gases at the same temperature and pressure contain equal numbers of molecules.
To solve this problem, we can use the following formula:
V1 / n1 = V2 / n2
where V1 is the initial volume of the gas, n1 is the initial number of moles of the gas, V2 is the final volume of the gas, and n2 is the final number of moles of the gas.
We can plug in the values given in the problem:
V1 / n1 = V2 / n2
V1 / 0.965 = V2 / 5.80
Solving for V2, we get:
V2 = (V1 / 0.965) * 5.80
V2 = (15.5 L / 0.965) * 5.80
V2 = 93.7 L
Therefore, the new volume of the gas will be 93.7 L.
Hope it helps
Answer:
We can use the ideal gas law to solve this problem, which states:
PV = nRT
where P is the pressure of the gas, V is its volume, n is the amount of gas in moles, R is the ideal gas constant, and T is the temperature. Since the temperature and pressure are constant, we can rearrange this equation to solve for the new volume:
V = (n2/n1) × V1
where n1 is the initial amount of gas, n2 is the final amount of gas, and V1 is the initial volume. Substituting the given values, we get:
V = (5.80 mol/0.965 mol) × 15.5 L
V = 93.3 L
Therefore, the new volume of the gas will be 93.3 L when the amount of gas is increased from 0.965 mol to 5.80 mol, assuming the temperature and pressure remain constant.