15J of work was done by an electric field on a +3C charge to accelerate it from point A to point B. What is the voltage across points A and B?
-5V
-20V
8V
-1V
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15J of work was done by an electric field on a +3C charge to accelerate it from point A to point B. What is the voltage across points A and B?
-5V
-20V
8V
-1V
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Explanation:
We can use the formula:
Work (W) = Charge (Q) x Voltage (V)
To find the voltage (V), we can rearrange the formula:
V = W/Q
Plugging in the values given:
V = (15J) / (+3C)
V = +5V
Since the charge is positive and the work done is positive, the voltage should also be positive. Therefore, the correct answer is 5V.