1.if y varies inveresly as x ,and y=48 when x=10,find y when x =32
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1.if y varies inveresly as x ,and y=48 when x=10,find y when x =32
1.if y varies inveresly as x ,and y=48 when x=10,find y when x =32
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Answer:
Formula of inverse variation: y = k/x
Substitute: 48 = k/10
Multiply both sides by 10 to cancel out and eliminate denominator:
10(48) = (k/10)10
480 = k
Solve for y:
y = k/x
y = 480/32
y = 15