If y = |2 sin(2πx - π/2) - 1|, the the largest possible value for y (for real x) is:
A. 1
B. 2
C. 3
D. 0
E. None of the above
Please with answer and solution... :))
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If y = |2 sin(2πx - π/2) - 1|, the the largest possible value for y (for real x) is:
A. 1
B. 2
C. 3
D. 0
E. None of the above
Please with answer and solution... :))
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Answer:
The above relation can be related to : y = mx + b
Since it is in modulus, b = 3.
Also, this equation, when graphed, has the y-intercept = 3.
So 3 is the correct value.
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