List the first five terms in the following relationship
4. an = 3n - 2
5. an = (4n + 1 )/2
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List the first five terms in the following relationship
4. an = 3n - 2
5. an = (4n + 1 )/2
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Answer:
4) an = 3n - 2
a1 = 3(1) - 2
a1 = 3 - 2
a1 = 1
a2 = 3(2) - 2
a2 = 6 - 2
a2 = 4
a3 = 3(3) - 2
a3 = 9 -2
a3 = 7
a4 = 3(4) - 2
a4 = 12 - 2
a4 = 10
a5 = 3(5) - 2
a5 = 15 - 2
a5 = 13
5) a1 = [4(1) + 1] 2
a1 = (4 + 1) 2
a1 = (5) 2
a1 = 10
a2 = [4(2) + 1] 2
a2 = (8 + 1) 2
a2 = (9) 2
a2 = 18
a3 = [4(3) + 1] 2
a3 = (12 + 1) 2
a3 = (13) 2
a3 = 26
a4 = [4(4) + 1] 2
a4 = (16 + 1) 2
a4 = (17) 2
a4 = 34
a5 = [4(5) + 1] 2
a5 = (20 + 1) 2
a5 = (21) 2
a5 = 42
ps. jusme kapagod mag-type, mag-aral ka mabuti ha. reviewhin mo ‘to kung maaari.
Step-by-step explanation:
4.)an=3(1)-2 = 1
=3(2)-2= 4
=3(3)-2= 7
=3(4)-2= 10
=3(5)-2= 13
5.)an=[4(1)+1]/2 = 2.5
=[4(2)+1]/2 = 4.5
=[4(3)+1]/2 = 6.5
=[4(4)+1]/2 = 8.5
=[4(5)+1]/2 = 10.5