two faucets can fill a tank in 1and1/3 hours the first faucets take more than two hours longer to fill the same tank when functioning without the second tap how long does it take to fill each one separately
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two faucets can fill a tank in 1and1/3 hours the first faucets take more than two hours longer to fill the same tank when functioning without the second tap how long does it take to fill each one separately
complete solution
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Step-by-step explanation:
time needed by 2nd faucet alone --- t hrs
rate for 2nd faucet alone =
t
1
time needed by 1st faucet alone --- t+2 hrs
rate of 1st faucet along =
(t+2)
1
combined rate =
t
1
+
(t+2)
1
=
(t(t+2)
(t+2+t)
=
(t(t+2))
(2t+2)
= 4/3
(2t+2)
t(t+2)
=3
4
3t
2
+6t=8t+8
3t
2
−2t−8=0
(t−2)(3t+4) = 0
t = 2 or t = a negative time
the 2nd faucet would take 2 hours alone
the 1st facucet would take 4 hours alone
Answer:
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Step-by-step explanation:
131 or 122 or 111111