3. Solve for the value of the discriminant and determine the nature of the roots. Show your solution.
3.1) x2 + 9x - 7 = 0
3.2) x2 + 6x - 3 = 0
3.3) x2 - 10x + 25 = 0
3.4) 3x2 - 5x + 7 = 0
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3. Solve for the value of the discriminant and determine the nature of the roots. Show your solution.
3.1) x2 + 9x - 7 = 0
3.2) x2 + 6x - 3 = 0
3.3) x2 - 10x + 25 = 0
3.4) 3x2 - 5x + 7 = 0
I need your help
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Answer:
1. x²+9x-7=0
Use the Discriminant formula,
D=9²-4(1)(-7)
Simplify the expression,
D=109 and it has 2 real solutions
2. x²+6x-3=0
Use the Discriminant formula,
D=6²-4(1)(-3)
Simplify the expression,
D=48 and it has 2 real solutions
3. x²-10x+25=0
Use the Discriminant formula,
D=(-10)²-4(1)(25)
Simplify the expression,
D=0 and it has 1 real solution
4. 3x²-5x+7=0
Use the Discriminant formula,
D=(-5)²-4(3)(7)
Simplify the expression,
D=-59 and it has no real solution
pabrainliest po
Finding the Value of the Discriminant and Determine the the Nature of Roots
In solving for the Discriminant, use the formula b^2-4ac
Determining the Nature of Roots
ANSWER
1. x^2+9x-7=0
a= 1 b= 9 c= -7
(9)^2-4(1)(-7)
81+28= 109
Nature of Roots is Real Irrational Unequal
2. x^2+6x-3=0
a= 1 b= 6 c= -3
(6)^2-4(1)(-3)
36+12= 48
Nature Of Roots is Real Irrational Unequal
3. x^2-10x+25=0
a=1 b= -10 c= 25
(-10)^2-4(1)(25)
100-100= 0
Nature of Roots is Real Rational Equal
4. 3x^2-5x+7=0
a= 3 b= -5 c= 7
(-5)^2-4(3)(7)
25-84= -59
Nature of Roots is Not Real
Always do Remember the Negative Sign
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