3.in which circuit did the bulb light up?why
4.in which circuit did the bulb not light up?why
Share
3.in which circuit did the bulb light up?why
4.in which circuit did the bulb not light up?why
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Verified answer
Answer:
3. Both the metal casing and tip of the bulb are connected to the circuit, forming a closed circuit. Thus, electricity is able to flow through the wires in the circuit to the filament, allowing the bulb to light up.
4. It cannot flow in an open circuit because there will be no potential difference b/w the two ends.So, no electrons will flow. Hence no current will flow.
#Carryonlearning
Verified answer
Answer:
3.Both the metal casing and tip of the bulb are connected to the circuit, forming a closed circuit. Thus, electricity is able to flow through the wires in the circuit to the filament, allowing the bulb to light up.
Circuit Example
If the light bulbs are connected in parallel, the current flowing through the light bulbs combine to form the current flowing in the battery, while the voltage drop is 6.0 V across each bulb and they all glow. In a series circuit, every device must function for the circuit to be complete.
4. In open circuit, the path is broken. So electron cannot maintain its flow. When the flow is stopped, energy transferred to light bulb also stopped and the