40 random part time college student has mean monthly earnings of ₱3,245 and standard deviation of ₱567. What is the 90% confidence interval?
a.
₱3,097.97 - ₱3,392.03
b.
₱2,678 - ₱3812
c.
₱2,410.20 - ₱3,430.80
d.
₱3,165 - ₱3,3602
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40 random part time college student has mean monthly earnings of ₱3,245 and standard deviation of ₱567. What is the 90% confidence interval?
a.
₱3,097.97 - ₱3,392.03
b.
₱2,678 - ₱3812
c.
₱2,410.20 - ₱3,430.80
d.
₱3,165 - ₱3,3602
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Answer:
To calculate the 90% confidence interval for the mean monthly earnings of the 40 random part time college students with a mean of ₱3,245 and standard deviation of ₱567, we can use the following formula:
Confidence Interval = x̄ ± z*(s/√n)
Where:
- x̄ = sample mean
- z = z-score, which is the number of standard deviations corresponding to the confidence level, in this case 90%, so z = 1.645
- s = sample standard deviation
- n = sample size
Substituting the given values, we have:
Confidence Interval = ₱3,245 ± 1.645 * (₱567/√40)
Simplifying this expression, we get:
Confidence Interval = ₱3,245 ± ₱166.16
So the 90% confidence interval for the mean monthly earnings of the 40 random part time college students is from ₱3,078.84 to ₱3,411.16
Step-by-step explanation:
the answer is A