5 red 2 white and 3 blue balls are arranged in a row if the balls of light colors are not distinguished from each other how many possible ways can be ordere
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5 red 2 white and 3 blue balls are arranged in a row if the balls of light colors are not distinguished from each other how many possible ways can be ordere
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Answer:
8! ÷ 5!2!3!
= 8×7×6 ÷ 2×1×3×2×1
= 336 ÷ 12
= 28
So it can be done in 28 ways