A 2.0 L sample at 20°C and 750 torr contains 0.5moles of a gas. If 0.1 mole of the gas at the same temperature and pressure is added to the sample, what is the new volume of the gas
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A 2.0 L sample at 20°C and 750 torr contains 0.5moles of a gas. If 0.1 mole of the gas at the same temperature and pressure is added to the sample, what is the new volume of the gas
show the solution
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Answer: The gas in the sample is at standard temperature and pressure (STP) conditions, which are defined as 0°C and 1 atm (101.325 kPa). To find the new volume of the gas, we need to use the Ideal Gas Law, which states that PV = nRT.
The initial volume of the gas is 2.0 L, the initial number of moles is 0.5, and the temperature is 20°C, which is equivalent to 293.15 K. Using these values, we can calculate the initial pressure (P) using the equation:
PV = nRT
P = (nRT) / V
P = (0.5 * 8.314 * 293.15) / 2.0
P = 890.8 torr
After 0.1 mole of the gas is added, the total number of moles becomes 0.6. To find the new volume of the gas, we can use the Ideal Gas Law again and the pressure remains constant,
V = nRT / P
V = (0.6 * 8.314 * 293.15) / 890.8
V = 2.1 L
The new volume of the gas is 2.1 L after 0.1 mole of the gas is added to the sample.
Explanation:
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