A 50N force is applied to a 100kg boulder for 3 sec. what is the velocity of the boulder?
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A 50N force is applied to a 100kg boulder for 3 sec. what is the velocity of the boulder?
A 50N force is applied to a 100kg boulder for 3 sec. what is the velocity of the boulder?
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Answer:
F = m * a
In this case, the force applied to the boulder is 50 N, and the mass of the boulder is 100 kg. We need to calculate the acceleration. Rearranging the formula, we have:
a = F / m
a = 50 N / 100 kg
a = 0.5 m/s²
The acceleration of the boulder is 0.5 m/s².
Now, we can use another formula to find the velocity (v) of the boulder, given the initial velocity (u) as 0 (assuming the boulder starts from rest), acceleration (a) as 0.5 m/s², and time (t) as 3 seconds:
v = u + a * t
v = 0 + 0.5 m/s² * 3 s
v = 1.5 m/s
Therefore, the velocity of the boulder after 3 seconds of applying a 50 N force is 1.5 m/s.
Explanation: