a 860 kg car traveling at 16.6 ms slows down to 5.56 ms in 10s as it approaches a road intersection what is the force applied in the brakes of the car what is the impulse exerted on the vehicle
Share
a 860 kg car traveling at 16.6 ms slows down to 5.56 ms in 10s as it approaches a road intersection what is the force applied in the brakes of the car what is the impulse exerted on the vehicle
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Answer:
First calculate the impulse:
Δp = m v
Δp = 60 kg x 3 m/s
Δp = 180 kg m/s
Stopping in 0.05 s:
F = ΔpΔt
F = 180 kg m/s0.05 s = 3600 N
Stopping in 0.2 s:
F = ΔpΔt
F = 180 kg m/s0.2 s = 900 N
Answer:
900 N
Wait di ba in answer KO na to haha
Carry On Learning