A basketball team won 60% of the game in 3 seasons if they played 45 games, how many did they won
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A basketball team won 60% of the game in 3 seasons if they played 45 games, how many did they won
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Answer:
They won 27 games
Step-by-step explanation:
Formula: Percentage = Base × Rate
45 × .60 = 27
Answer:
Let x be the number of games at first point where 60% was won and after that point they won another 8 games where they lost 2 to finish the season with 65% winning percentage.
At first point, winning 0.60x but lost 0.40x and another winning 8 games out of 10 games with 2 losses:
Number of games at 1st point= x
Number of games at 2nd point=10
Total Games = x+10
Total wins= 0.60x + 8
But the winning percentage of 65% of the total games equal to the total number of wins represented by the following algebraic expression:
0.65(x+10)=0.60x+8
0.65x+ 6.5=0.60x+8
O.65x-0.60x=8–6.5
0.05x=1.5
x=1.5/0.05
x=30 games at 1st point
Total number of games =30+10= 40 games (answer)
1st Point = winning 60% of 30= 18 games and lost 40% of 30= 12 games
2nd Point= winning 8 games but lost 2 games
Total wins=18+8=26 wins
Total losses=12+2=14 losses
Winning Percentage =(26/40)x100=0.65x100=65% OK