A sample of Neon gas occupies a volume of 0.50L at 1.70atm. What will be its volume at 30kPa?
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A sample of Neon gas occupies a volume of 0.50L at 1.70atm. What will be its volume at 30kPa?
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Answer:
A sample of Neon gas occupies a volume of 0.50 L at 1.70 atm. What will be its volume at 30 kPa?
Given Data:
V₁ ( initial volume ) = 0.50 L V₂ ( Final volume ) = ? unknown
P₁ ( Initial Pressure ) = 1.70 atm P₂ ( Final pressure ) = 30 kPa ( 0.3 atm )
Solution:
We can solve the problem using the formula ( V₂ = P₁V₁ / P₂ )
V₂ = P₁V₁ / P₂
= 1.70 atm × 0.50 L / 0.3 atm
= 2.83 L
Answer:
The final volume is equal to 2.83 L
Explanation:
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