A speed boat travels at a rate of 20 kph in still water.It travels 55 km upstream in the same time that it travels 90 km downstream.What is the rate of the current?
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A speed boat travels at a rate of 20 kph in still water.It travels 55 km upstream in the same time that it travels 90 km downstream.What is the rate of the current?
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Answer:
makinig kapag nagtuturo ang guro hindi kung ano ano ang nasa isp mo
Step-by-step explanation:
mag aral ng mabuti ha ito na sagut
rate = (20-c)km/h ; distance = 55 km ; time = d/r = 55/(20-c) hrs.
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Downstream DATA:
rate = (20+c)km/h ; distance = 90 km ; time = 90/(20+c) hrs.
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Equation:
time up = time down
55/(20-c) = 90/(20+c)
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55*20 + 55c = 90*20 - 90c
145c = 35*20
c = (7/29)*20
c = 140/29 = 4.83 km/h (rate of the current)