A.
1.x²=225
2.3x-4=6x²
3.8+2x=-x²
4.10x+5x²=12
B.Nasa pic na po.
PA ANSWER PO NG MAAYOS THANKS!
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A.
1.x²=225
2.3x-4=6x²
3.8+2x=-x²
4.10x+5x²=12
B.Nasa pic na po.
PA ANSWER PO NG MAAYOS THANKS!
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Verified answer
Answer:
1. x = ±15
[tex]\mathrm{2.\: x=\frac{1}{4}\pm\: i\frac{\sqrt{87}}{12}}[/tex]
[tex]\mathrm{3.\:x=-1\pm\sqrt{7}i}[/tex]
[tex]\mathrm{4.\:x=\pm\frac{-5+\sqrt{85}}{5}}[/tex]
Step-by-step explanation:
[tex]\mathrm{1.\: x^2 = 225}\\\\\mathrm{x = \sqrt{225}}\\\\\mathrm{x = \pm{15}}[/tex]
[tex]\mathrm{2.\: 3x - 4 = 6x^2}\\\\\mathrm{6x^2=3x-4}\\\\\mathrm{6x^2 - 3x + 4= 0}\\\\\mathrm{x_{1,\:2}=\frac{-\left(-3\right)\pm \sqrt{\left(-3\right)^2-4\cdot \:6\cdot \:4}}{2\cdot \:6}}\\\\\mathrm{x_1=\frac{-\left(-3\right)+\sqrt{87}i}{2\cdot \:6},\:x_2=\frac{-\left(-3\right)-\sqrt{87}i}{2\cdot \:6}}\\\\\mathrm{x=\frac{1}{4}\pm\: i\frac{\sqrt{87}}{12}}[/tex]
[tex]\mathrm{3.\: 8+2x=-x^2}\\\\\mathrm{-x^2=8+2x}\\\\\mathrm{-x^2 - 2x - 8 = 0}\\\\\mathrm{x_{1,\:2}=\frac{-\left(-2\right)\pm \sqrt{\left(-2\right)^2-4\left(-1\right)\left(-8\right)}}{2\left(-1\right)}}\\\\\mathrm{x_{1,\:2}=\frac{-\left(-2\right)\pm \:2\sqrt{7}i}{2\left(-1\right)}}\\\\\mathrm{x=-1\pm\sqrt{7}i}[/tex]
[tex]\mathrm{4.\: 5x^2+10x-12=0}\\\\\mathrm{x_{1,\:2}=\frac{-10\pm \sqrt{10^2-4\cdot \:5\left(-12\right)}}{2\cdot \:5}}\\\\\mathrm{x=\pm\frac{-5+\sqrt{85}}{5}}[/tex]