Activity A Copy and complete the following table for each circle. Use 3.14 for the value of TT. 1. 2. 5. Radius Diameter Area 11 cm 109.9 cm² 3. 40 mm 4. 6 ft 15 m
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Activity A Copy and complete the following table for each circle. Use 3.14 for the value of TT. 1. 2. 5. Radius Diameter Area 11 cm 109.9 cm² 3. 40 mm 4. 6 ft 15 m
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Step-by-step explanation:
1.) Diameter = 2 x Radius
Diameter = 2 x 11 cm
Diameter = 22 cm
Area = π x radius²
Area = π x (11 cm)²
Area = π x 121 cm²
Area = 380.13 cm² (rounded to two decimal places)
2.) Area = π x radius²
Substituting the given area of 109.9 cm², we get:
109.9 cm² = π x radius²
Solving for the radius, we get:
radius² = 109.9 cm² / π
radius² = 35 cm
radius = √35 cm (rounded to two decimal places)
radius = 5.92 cm (rounded to two decimal places)
diameter = 2 x radius
diameter = 2 x 5.92 cm
diameter = 11.84 cm
3.) radius = diameter / 2
radius = 40 mm / 2
radius = 20 mm
Area = π x radius²
Area = π x (20 mm)²
Area = π x 400 mm²
Area = 1256.64 mm² (rounded to two decimal places)
4.) diameter = 2 x radius
diameter = 2 x 8 ft
diameter = 16 ft
Area = π x radius²
Area = π x (8 ft)²
Area = π x 64 ft²
Area = 201.06 ft² (rounded to two decimal places)
5.) radius = diameter / 2
radius = 15 m / 2
radius = 7.5 m
Area = π x radius²
Area = π x (7.5 m)²
Area = π x 56.25 m²
Area = 176.71 m² (rounded to two decimal places)