Add the sum of 4y² + 15y + 9 and -3y² - 12 to the sum of - 8y + 24 and -15y²+ 6y + 4.
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Add the sum of 4y² + 15y + 9 and -3y² - 12 to the sum of - 8y + 24 and -15y²+ 6y + 4.
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Answer:
4y[tex]^{2}[/tex]+15y+9 = (4y+3)(y+3)
-3[tex]y^{2}[/tex]-12 = 3(y-2)(y+2)
-8y+24 = 8(y+3)
-15[tex]y^{2}[/tex]+6y+4 = simplified
step-by-step explanation:
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