Answer the following Charles’ Law problems:
1. A 4.5 L flexible container holds a gas at 300 K. What will be the new volume if the temperature is increased to 400 K?
2. A balloon has a volume of 685 mL at 34°C. If the temperature drops to 0°C, what is the new volume of the balloon (P constant)?
Share
Answer:
1. Using Charles' Law (V1/T1 = V2/T2), we can set up the equation:
4.5 L/300 K = V2/400 K
Solving for V2, we get:
V2 = (4.5 L/300 K) * 400 K
V2 = 6 L
Therefore, the new volume is 6 L.
2. Using Charles' Law (V1/T1 = V2/T2), we can set up the equation:
685 mL/307 K = V2/273 K
Solving for V2, we get:
V2 = (685 mL/307 K) * 273 K
V2 = 610 mL
Therefore, the new volume is 610 mL.