ASAP PRECAL
The cable of suspension bridge hangs in the form of parabola when the load is non uniform distributed horizontally the distance between the two towers is 150 m the lowest point the lowest point is 7m above the floor of the bridge, the point of support of the cable on the tower are 22m above the road wat. find the height of the cable at a point 15m from each tower?
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Problem:
The cable of suspension bridge hangs in the form of parabola when the load is non uniform distributed horizontally the distance between the two towers is 150 m the lowest pt is 7m above the floor of the bridge, the pt of support of the cable on the tower are 22m above the road. Find the height of the cable at a pt 15m from each tower?
Solution:
x² = 4ay
(x, y)
(75, 15)
75² = 4a(15)
5625 = 60a
5625/60 = a
a = 93.75
x² = 4ay
x² = 4(93.75)y
x² = 375y
The distance from the center to the 15m pt
75 - 15 = 60m
x² = 375y
60² = 375y
3600 = 375y
3600/375 = y
y = 9.6m
Since there is a symmetry on the parabola, the height of the cable at a pt 15m from each tower is 9.6m
Answer:
y = 9.6m
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