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Assume that you are to buy 5-peso worth of candy on two different stores. In your coin purse that contains two 20-peso coin, three 10-peso coin, six 5-peso coin, and seven 1-peso coin, what is the probability of getting two consecutive 5-peso coin from your purse assuming that you already paid the first store a 5-peso coin before getting another 5-peso coin from your purse to pay the second store?
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Answer:
To compute the probability of getting two consecutive 5-peso coins, we first need to determine the total number of 5-peso coins left in the purse after paying the first store.
Since you paid the first store with a 5-peso coin, you have five 5-peso coins left in your purse. The probability of drawing one of these coins on the first draw is 5/46 (since there are a total of 46 coins in the purse).
After drawing the first coin, there are four 5-peso coins left in your purse, along with 45 total coins. The probability of drawing another 5-peso coin on the second draw is 4/45.
To get the probability of getting two consecutive 5-peso coins, we multiply the probabilities of each draw:
P(5-peso coin, then another 5-peso coin) = (5/46) * (4/45) = 0.001
Therefore, the probability of getting two consecutive 5-peso coins from your purse is 0.001 or 0.1%.
Step-by-step explanation: