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What is the probability of getting a seven on two consecutive draws on a normal deck of cards without putting back the first card drawn to the deck?
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What is the probability of getting a seven on two consecutive draws on a normal deck of cards without putting back the first card drawn to the deck?
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Answer:
The probability of getting a seven on the first draw is 4/52, since there are 4 sevens in a deck of 52 cards. After the first card is drawn, there are now 51 cards remaining in the deck, and 3 sevens left, so the probability of getting a seven on the second draw, given that a seven was not drawn on the first draw, is 3/51.
To calculate the probability of getting a seven on two consecutive draws, we need to multiply the probability of getting a seven on the first draw by the probability of getting a seven on the second draw, given that a seven was not drawn on the first draw:
(4/52) * (3/51) = 0.0045, or approximately 0.45%.
Therefore, the probability of getting a seven on two consecutive draws on a normal deck of cards without putting back the first card drawn to the deck is approximately 0.45%.
Step-by-step explanation: