B. Given: y2x² +20x+50 c. direction of the opening of the graph d. axis of symmetry e domain f range E arros of the function h. Sketch the graph
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B. Given: y2x² +20x+50 c. direction of the opening of the graph d. axis of symmetry e domain f range E arros of the function h. Sketch the graph
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Step-by-step explanation:
c. Direction of the opening of the graph:
- The coefficient of \(x^2\) term is positive (2 in this case), which means the graph opens upwards.
d. Axis of symmetry:
- The axis of symmetry for a quadratic function in the form \(y = ax^2 + bx + c\) is given by \(x = \frac{-b}{2a}\). In this case, \(a = 2\) and \(b = 20\), so the axis of symmetry is \(x = \frac{-20}{2(2)} = -5\).
e. Domain:
- The domain of a quadratic function is all real numbers, since it is defined for all possible values of \(x\).
f. Range:
- Since the graph opens upwards, the minimum value occurs at the vertex. The range will be all real numbers greater than or equal to the y-coordinate of the vertex.
To find the y-coordinate of the vertex, substitute \(x = -5\) into the equation:
\(y = 2(-5)^2 + 20(-5) + 50 = 50 - 100 + 50 = 0\).
So, the range is all real numbers \((-\infty, \infty)\).
h. Sketching the graph:
- I can't draw graphs directly, but I can describe it to you. Since the graph opens upwards and the vertex is at (-5, 0), it will be a parabola that touches the x-axis at \(x = -5\) and extends upwards.