calculate the following given problem:
What is the temperature of a 2.3 L balloon if it shrinks to a volume of 0.632 L when it is dipped into
liquid nitrogen at a temperature of 77 F?
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calculate the following given problem:
What is the temperature of a 2.3 L balloon if it shrinks to a volume of 0.632 L when it is dipped into
liquid nitrogen at a temperature of 77 F?
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Answer:
T1=280K
Explanation:
Formula:
V1/T1=V2/T2
T1=?
T2=77K
V1= 2.3L
V2= 0.632L
Sol.
2.3L/T1=0.632L/77K
T1=(2.3L)(77k)/0.632L
T1=280K