Calculate the molality of a sulfuric acid solution containing 34.2 g of sulfuric acid in 173 g of water.
Home
/
Calculate the molality of a sulfuric acid solution containing 34.2 g of sulfuric acid in 173 g of water
Calculate the molality of a sulfuric acid solution containing 34.2 g of sulfuric acid in 173 g of water.
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Verified answer
SOLUTION:
Step 1: List the given values.
[tex]\begin{aligned} & mass_{\text{solute}} = \text{34.2 g} \\ & MM_{\text{solute}} = \text{98.08 g/mol} \\ & mass_{\text{solvent}} = \text{173 g = 0.173 kg} \end{aligned}[/tex]
Step 2: Calculate the number of moles of solute.
[tex]\begin{aligned} n_{\text{solute}} & = \frac{mass_{\text{solute}}}{MM_{\text{solute}}} \\ & = \frac{\text{34.2 g}}{\text{98.08 g/mol}} \\ & = \text{0.34869 mol} \end{aligned}[/tex]
Step 3: Calculate the molality of solution.
[tex]\begin{aligned} m & = \frac{n_{\text{solute}}}{mass_{\text{solvent}}} \\ & = \frac{\text{0.34869 mol}}{\text{0.173 kg}} \\ & = \text{2.02 mol/kg} \\ & = \boxed{2.02 \: m} \end{aligned}[/tex]
Hence, the molality of the solution is 2.02 m.
[tex]\\[/tex]
#CarryOnLearning