Charges E and F are situated 4.44 m apart. What is the magnitude of the electric charge of particle F if particle E has 11.2 μC and their UE is 914 J?
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Charges E and F are situated 4.44 m apart. What is the magnitude of the electric charge of particle F if particle E has 11.2 μC and their UE is 914 J?
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Answer:
0.0403 C
Explanation:
qD=UE(R) / kqc
= (914 J)(4.44m) / (9.0 x 10^9)(11.2 x 10^-6)
= 4,058.16 / 100,800
=0.0403 C