ctivity 2
olve the following problems.
The side of a square is 5 cm. If its side is doubled, how many times is
the area of the new square bigger than the area of the old square?
Rectangle ABCD has a length of 8 cm and a width of 6 cm. What is the
total area of the blue rectangles?
р 6 cm
8
8 cm
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A = S^2
A = (5cm)^2
A = 25 cm^2
A = (2S)^2
A = (2 x 5cm)^2
A = (10cm)^2
A = 100 cm^2
The area of the new square is quadruple the area of the old square.
2.
A = LW
A = (8cm)(6cm)
A = 48 cm^2
Answer:
A=s square
A=5x5=25
A=s square
a=(5x2) square
A=10x10
A=100
therefore the new are of square is 4x the old are of the square
A=lxw
A=8cmx6cm
A=48cmsquare