(Delton's Law of Partial Pressure)
1. The regulator on a steel scuba tank containing compressed air indicates that the pressure is 2250 psi. If the partial pressure of nitrogen is 1755 psi and that of argon is 22 psi, what is the partial pressure of oxygen in the tank?
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SOLUTION:
Step 1: List the given values.
[tex]\begin{aligned} & P_{\text{N}_2} = \text{1755 psi} \\ & P_{\text{Ar}} = \text{22 psi} \\ & P_{\text{T}} = \text{2250 psi} \end{aligned}[/tex]
Step 2: Calculate the partial pressure of O₂ by using Dalton's law of partial pressures.
[tex]\begin{aligned} P_{\text{T}} & = P_{\text{N}_2} + P_{\text{Ar}} + P_{\text{O}_2} \\ P_{\text{O}_2} & = P_{\text{T}} - P_{\text{N}_2} - P_{\text{Ar}} \\ & = \text{2250 psi} - \text{1755 psi} - \text{22 psi} \\ & = \boxed{\text{473 psi}} \end{aligned}[/tex]
Hence, the partial pressure of oxygen gas in the tank is 473 psi.
[tex]\\[/tex]
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