Determine the length of .
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LK is the tangent →
the segment between K – point and
the central point of the circle lies at an angle of 90°
respect to LK.
If the central point of the circle is "O", then we have
the right-angled triangle ∆LKO, where
LO is the hypotenuse = 7.5 (half of JM = 15) + 5(LJ) ,
LO=12.5
OK is the radius of the circle → OK – ½MJ – 7.5
∆LKO is the right-angled with
hypotenuse = 12.5 and one of the cathet = 7.5, so using the Pythagorean theorem:
LK² = LO² – OK²
LK² = 12.5² – 7.5²
LK² = 156.25 – 56.25
LK² = 100
LK = 10
Answer: C