determine the standard form of equation of a circle
1.x2+y2+4x+2y=4
2.x2=36-y2
Share
determine the standard form of equation of a circle
1.x2+y2+4x+2y=4
2.x2=36-y2
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Answer:
The equation is equavilent to:
(x^2-4x+4)+(y^2-2y+1)-9 = 0
(x-2)^2+(y-1)^2 = 9 = 3^2
This is a circle that is centered at (2,1) with radius 3
Step-by-step explanation:
hope it helps and pa brainliest