Direction: Solve for the sample size based on the indicated population size and margin of error
1. N= 4.600 and e = 2.596
2. N=11.000 and e = 796
3 N = 5 800 and e = 396
Direction: Find the mean, median, mode and range of the following data sets
1.77.55, 43, 43, 64.9
2. 60.60. 61. 63
3.86 56. 86. 54, 107
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[tex]{\mathbb{\colorbox {purple}{\boxed{\boxed{\boxed{\boxed{\boxed{\colorbox {lime} {\boxed{\boxed{\boxed{\boxed{\boxed{\colorbox {aqua}{answer is complete}}}}}}}}}}}}}}}[/tex]
[tex]\fcolorbox{red}{yellow}{complete solution } [/tex]
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[tex]{\huge{\boxed{\boxed{\mathcal{\blue{test. ll!}}}}}}[/tex]
[tex] = > formula \\ = > n = \frac{n}{1 + ne {}^{2} } \\ \\ solution \\ 1. = > n = \frac{n}{1 + ne {}^{2} } \\ = > n = \frac{4.600}{1 + (4.600)(0.025) {}^{2} } \\ = > \frac{4.600}{1 + 2.875} \\ = > n = \frac{4.600}{3.875 } \\ = > 1.187.096 \\ = > n1.187 \\ \\ 2. = > n = \frac{n}{1 + ne {}^{2} } \\ = > n = \frac{11.000}{1 + (11.000)(0.07) {}^{2} } \\ = > \frac{11.000}{1 + (11.000)(0.0049) } \\ = > n = \frac{11.000}{1 + 53.9} \\ = > \frac{11.000}{54.9} \\ = > n = 200.36 \\ \\ 3. = > \frac{n}{1 + ne {}^{2} } \\ = > n \frac{5.800}{1 + (5.800)(0.03) {}^{2} } \\ = > n \frac{5.800}{1 + (5.800)(0.0009) } \\ = > n \frac{5.800}{1 + 5.22 } \\ = > n = 192.47[/tex]
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[tex]{\huge{\boxed{\boxed{\mathcal{\blue{test. lll}}}}}}[/tex]
1 mean=77,65,43,43,64,9
= 77+65+43+43+64+9=301
[tex]\fcolorbox{red}{yellow}{ANSWER} [/tex] = 301÷6 = 50.16
meadian = 9,43,43,64,65,77
=(43+64)=107
[tex]\fcolorbox{red}{yellow}{ANSWER} [/tex] =107÷2=53.5
[tex]\fcolorbox{red}{yellow}{ANSWER} [/tex]mode = 43
2. mean= 60,60,61,63
= 60+60+61+63=244
[tex]\fcolorbox{red}{yellow}{ANSWER} [/tex] = 244÷4=61
median = 60,60,61,63
=(60+61)=121
[tex]\fcolorbox{red}{yellow}{ANSWER} [/tex] = 121÷2= 60.5
[tex]\fcolorbox{red}{yellow}{ANSWER} [/tex]mode = 60
3. mean = 86,56,86,54,107
= 86+56+86+54+107=389
[tex]\fcolorbox{red}{yellow}{ANSWER} [/tex] =389÷5=77.8
madian= 54,56,86,86,107
[tex]\fcolorbox{red}{yellow}{ANSWER} [/tex]= 86
[tex]\fcolorbox{red}{yellow}{ANSWER} [/tex]mode =86
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