Enrichment:
Solve each problem.
1.) If the 3rd term of an arithmetic sequence is 15 and the 6th term is 30, what is the 15th
term?
2.) If the 8th term of an arithmetic sequence is 18 and the 12th term is 26, what is the 20th
term?
3.) If the 4th term of an arithmetic sequence is 42 and the 6th term is 34, what is the 10th
term?
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Verified answer
Answer:
1. 15th term is 70
2. 20th term is 42
3. 10th term is 18
Step-by-step explanation:
1. Just add 5 in every nth term.
2. Just add 2 in every nth term.
3. Just subtract 4 in every nth term.
Answer:1.) 75
2.) 42
3.) 18
Step-by-step explanation: a15 = 5 +( 15-1)5
a15=5+(14) 5
a15=5+70
a15=75
a20=4+(20-1)2
a20=4+(19) 2
a20=4+38
a20=42
a10=54+(10-1)-4
a10=54+(9)-4
a10=54+-36
a10=18