evaluate the following algebraic expression for x=2,=-1 and z =3.
1.) xyz
2.)2x³–3y²
3.)2x²yz–3xyz²+x²yz²
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evaluate the following algebraic expression for x=2,=-1 and z =3.
1.) xyz
2.)2x³–3y²
3.)2x²yz–3xyz²+x²yz²
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Answer:
1.) xyz
(2)(-1)(3)
-2(3)
= -6
2.) 2x³- 3y²
2(2)³ - 3(-1)²
2(8) - 3(1)
16 - 3
= 13
3.) 2x²yz - 3xyz² + x²yz²
2(2)²(-1)(3) - 3(2)(-1)(3)² + (2)²(-1)(3)²
2(4)(-3) - 6(-1)(9) + 4(-1)(9)
8(-3) + 6(9) - 4(9)
-24 + 54 - 36
54 - 60
= -6
Step-by-step explanation:
Correct me if I'm wrong.