Express (a-²b-⁵) into nonnegative power brainliest answer ko Naman Tamang sagut ehh
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Express (a-²b-⁵) into nonnegative power brainliest answer ko Naman Tamang sagut ehh
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Answer:
[tex]ANG SAGOT!
1. \: {( {a}^{ - 2} b)}^{5} = {a}^{ - 10} {b}^{5} \: or \: \frac{1}{ {a}^{10} } {b}^{5}1.(a−2b)5=a−10b5ora101b5
2. \: {( {a}^{6} {b}^{ - 6} )}^{ - 1} = {a}^{ - 6} {b}^{6} \: or \: \frac{1}{ {a}^{6} } {b}^{6}2.(a6b−6)−1=a−6b6ora61b6
3. \: {( \frac{ {g}^{ - 6} }{ {g }^{ - 3} } })^{ - 2} = {( {g}^{ - 3} )}^{ - 2} = {g}^{6}3.(g−3g−6)−2=(g−3)−2=g6
4. \: { {( - 5c}^{ - 3} )}^{4} = 625 {c}^{ - 12} \: or \: 625\frac{1}{{c}^{12} }4.(−5c−3)4=625c−12or625c121
5. \: {( \frac{ {10}^{2} }{ {10}^{ - 5} } )}^{0} = 15.(10−5102)0=1
6. \: ( \frac{ {5}^{ - 2}}{ {5}^{ - 2} } ) = {5}^{0} = 16.(5−25−2)=50=1
7. \: {( \frac{ {8}^{0} }{8}) }^{ - 2} = {( \frac{1}{8} )}^{ - 2} = 647.(880)−2=(81)−2=64
8. \: ( \frac{15 {n}^{ - 4} p}{5 {n}^{3} } ) = \frac{p}{3 {n}^{ - 7} }8.(5n315n−4p)=3n−7p
9. \: ( \frac{121 {x}^{ - 4} {u}^{2} }{11 x{u}^{4} } ) = 11 {x}^{ - 5} {u}^{ - 2} \: or \: 11 \frac{1}{ {x}^{5} {u}^{2} }9.(11xu4121x−4u2)=11x−5u−2or11x5u21
10. \: \frac{ {8}^{3} }{ {8}^{3} } = {1}^{0} = 110.8383=10=1
PA'NO EUN, LODS?!?
Narito ang ilang laws o rules sa pag-solve ng expression na may exponents (laws of exponents):
1. Addition of exponents. I-aadd mo lang ang dalawang exponents kung ang base nila ay nag-mumultiply.
{a}^{2} \times {a}^{5} = {a}^{5 + 2} = {a}^{7}a2×a5=a5+2=a7
2. Subtraction of exponents. Pwede mong gawin ito kapag ang base naman nila ay nagde-divide.
\frac{ {a}^{5} }{ {a}^{2} } = {a}^{5 - 2} = {a}^{3}a2a5=a5−2=a3
3. Multiplication of exponents. Gawin ito kapag napapagitnaan ng parenthesis o grouping symbols ang dalawang exponents.
{( {a}^{5}) }^{2} = {a}^{5 \times 2} = {a}^{10}(a5)2=a5×2=a10
4. Negative exponent. Kapag negative si exponent, gawing fraction ito at ilagay ang apektadong base sa denominator.
{a}^{ - 2} = \frac{1}{ {a}^{2} }a−2=a21
5. Zero exponent. Kapag zero si exponent, ang sagot lagi ay one.
{a}^{0} = 1a0=1
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