find the a19 of the arithmetic sequence -6, -13, -20, -27, -34
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find the a19 of the arithmetic sequence -6, -13, -20, -27, -34
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Answer:
-132 is the a19
Answer:
a19 = - 132
Solution:
Finding the common difference
d=a2-a1= - 13-(-6)= - 7
d=a3-a2= - 20-(-13)= - 7
d=a4-a3= - 27-(-20)= - 7
d=a5-a4= - 34-(-27)= - 7
D= - 7
Finding the 19th term
Formula: an=a1+(n-1)d
a19= - 6+(19-1) - 7
a19= - 6+(18) - 7
a19= - 6+(-126)
a19= - 132