find the area of the triangle whose height is 24 cm , and the base is ½ the length of the lenght
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find the area of the triangle whose height is 24 cm , and the base is ½ the length of the lenght
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Assuming the "length" mentioned in the problem refers to the length of the triangle's side opposite to the height:
Area of triangle = (base x height) / 2
Let the length of the side opposite to the height be L.
Then, the base of the triangle would be 1/2 * L.
Substituting the values given in the problem:
Area of triangle = (1/2 * L * 24) / 2
= (L * 12) / 2
= 6L
Therefore, the area of the triangle is 6 times the length of its opposite side (in square cm).