find the first five terms of each arithmetic sequence a1 = -13, d = 8
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find the first five terms of each arithmetic sequence a1 = -13, d = 8
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Answer:
-13, -5, 3, 11, 19
Explanation:
Use the formula an= a1+(n-1)d
To find the second term:
Given
a1= -13 d=8 n= 2
(n depends on what term you are looking for)
a2= -13+(2-1)8 Substitute
a2= -13+(1)8 Always solve what's inside the parenthesis first
a2= -13+8 Multiply 8 by 1
a2= -5
OR SINCE THE A1 AND D IS GIVEN, YOU CAN JUST DO THIS:
a2= a1+d
a2= -13+8
a2= -5
(This is only applicable if the 1st term and the common difference is given)
Now try looking for the 3rd, 4th, and 5th term by your self :)