find the first three terms of the sequence whose general term is given by an=-12n--16
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find the first three terms of the sequence whose general term is given by an=-12n--16
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Answer:
4,-8,-20
d=-12
Step-by-step explanation:
an=-12n--16
a1=-12(1)--16
a1=-12--16
a1=4
a2=-12(2)--16
a2=-24--16
a2=-8
a3=-12(3)--16
a3=-36--16
a3=-20
Answer:
1st = 4
2nd = -8
3rd = -20
Step-by-step explanation:
a1= -12(1)-(-16)
a1= -12-(-16)
a1= 4
a2= -12(2) -(-16)
a2= -24-(-16)
a2= -8
a3= -12(3) - (-16)
a3= -36-(-16)
a3=-20