find the product of (6z+3) (6z-3)
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Answer:
36z²-9
Step-by-step explanation:
FOIL METHOD
(6z)(6z)=36z²
(6z)(-3)=-18z
(3)(6z)=18z
(3)(-3)=-9
36z²-18z+18z-9, since -18+18 is equivalent to 0 we didn't excluded it in the answer. Therefore, the final answer is, 36z²-9.
Answer:
Step-by-step explanation:
(
6
z
2
−
5
z
−
2
)
(
3
z
3
−
2
z
−
4
)
Multiply each term in the expression
(
6
z
2
−
5
z
−
2
)
with
3
z
3
18
z
5
−
15
z
2
−
6
z
3
Multiply each term in the expression
(
6
z
2
−
5
z
−
2
)
with
−
2
z
18
z
5
−
15
z
2
−
6
z
3
−
12
z
3
+
10
z
2
+
4
z
Multiply each term in the expression
(
6
z
2
−
5
z
−
2
)
with
−
4
18
z
5
−
15
z
2
−
6
z
3
−
12
z
3
+
10
z
2
+
4
z
−
24
z
2
+
20
z
+
8
Group all the like terms
18
z
5
−
6
z
3
−
12
z
3
−
15
z
2
+
10
z
2
−
24
z
2
+
4
z
+
20
z
+
8
Simplify
18
z
5
−
18
z
3
−
29
z
2
+
24
z
+
8