find the quadratic equation whose roots are given below
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find the quadratic equation whose roots are given below
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Answer:
Answer:
1. x²-9x-36=0
2. x²+12x + 35=0
3.
Solution:
1. x²-9x-36=0.
(x-12) (x+3) =0
x-12=0 ; x+3=0
x=12. ; x=-3.
✅ ing x=12 ✅ ing x=-3
x²-9x-36=0. x²-9x-36=0.
12²-9(12)-36=0. -3 ²-9(-3)-36=0
144-108-36=0. 9+27-36=0
36-36=0. 36-36=0
0=0. 0=0
2. x²+12x + 35=0
(x+7) (x+5) =0
x+7=0 ; x+5=0
x = -7 ; x= -5
✅ ing x=-7 ✅ ing x=-5
x²+12x + 35=0. x²+12x + 35=0.
-7²+12(-7)+35=0. -5²+12(-5)+35=0
49-84+35=0. 25-60+35=0
-35+35=0. -35+35=0
. 0=0. 0=0
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