find the root of each quadratic equation by factoring. show your solution.
1. 2x²-6x=0
2. x²+22x+121=0
3. x²-625=0
4. 4a²+9a=9
5. 2(3a²-5)=8a+4
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find the root of each quadratic equation by factoring. show your solution.
1. 2x²-6x=0
2. x²+22x+121=0
3. x²-625=0
4. 4a²+9a=9
5. 2(3a²-5)=8a+4
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Answer:
1.
2x^2-6x=0
2x(x-3)=0 (Factorise the equation)
2x=0 OR x-3=0 (Zero product rule)
x=0 OR x=3
2.
x^2+22x+121=0
(x+11)(x+11)=0 (Factorise the equation)
x+11=0 OR x+11=0 (Zero product rule)
x=-11
3.
x^2-625=0
x^2=625
x^2=
= 25 OR -25
4.
4a^2+9a=9
4a^2+9a-9=0 (Equate the equation to zero)
(4a−3)(a+3)=0 (Factorise the equation)
4a-3=0 OR a+3=0 (Zero product rule)
4a=3 OR a=-3
a= 3/4 OR a=-3
5.
2(3a^2-5)=8a+4
6a^2-10=8a+4 (Expand the expression)
6a^2-10-8a-4=0 (Equate the equation to zero)
6a^2-8a-14=0
2(3a^2-4a-7)=0 (Simplify)
(3a−7)(a+1)=0 (Factorise the equation)
3a-7=0 OR a+1=0 (Zero product rule)
3a=7 OR a=-1
a= 7/3 OR a=-1
Hope this helped! :>